Material by the IntegralPaso project. Conditions and limits are stated in each guide; external teaching review is pending.
Here φ is the angle from the z axis, between 0 and π; θ is the azimuthal angle in the xy plane. We use x = r sinφ cosθ, y = r sinφ sinθ and z = r cosφ. The Jacobian is r² sinφ. For a full sphere, r runs from 0 to the radius, φ from 0 to π and θ from 0 to 2π.
Common mistake
Confusing the φ and θ convention or using r instead of r² sinφ for the Jacobian.
Choose spherical coordinates for balls and sectors and distinguish polar angle from azimuth.
When to choose this method
- The region depends on x²+y²+z² or distance from the origin.
- Fix the convention: here φ is measured from the positive z axis and θ around that axis.
Before calculating
- Describe radius, polar angle and azimuth before integrating.
- Transform the function and multiply by ρ² sinφ. In the editor the radius is named r.
A complete example, step by step
The region is a full ball of radius 2. The polar angle spans π, not 2π.
The sum of squares becomes ρ².
The function ρ² and Jacobian ρ² sinφ produce ρ⁴ sinφ.
Integrate the radial power before touching the angles.
The polar integral equals 2; the primitive minus sign matters.
Multiply by the azimuthal integral 2π.
Check the result and domain
For z≥0 replace φ≤π by φ≤π/2. For a full ball the polar angle runs from 0 to π under this convention.
Now try it yourself
Solve on paper before opening the hint or answer. These are self-assessment activities; to check a typed answer, open Learn.
Show a hint
Use integrand 1 and Jacobian ρ² sinφ.
Check my result
Show a hint
This is a half-ball; φ runs to π/2.
Check my result
Show a hint
The radial power is ρ⁴.