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Multiple variables

Cylindrical coordinates

Material by the IntegralPaso project. Conditions and limits are stated in each guide; external teaching review is pending.

dV=r dr dθ dzdV=r\,dr\,d\theta\,dz

Keep the vertical coordinate and describe the circular projection in polar coordinates. Heights may depend on r and θ. The Jacobian is r, not r².

Common mistake

Do not add r twice in the calculator: it is inserted automatically.

DEVELOPED GUIDE · 9 min

Use cylindrical coordinates for solids symmetric around the z axis with dependent bounds.

When to choose this method

  • The horizontal projection is circular and height is described by z and x²+y².
  • Cylindrical coordinates retain z and transform only the planar coordinates.

Before calculating

  1. Determine the projection and the lower and upper surfaces.
  2. Choose an order compatible with dependencies. The calculator integrates dr, dθ, dz in cylindrical coordinates.

A complete example, step by step

V=∭0≤z≤4−x2−y21 dVV=\iiint_{0\le z\le4-x^2-y^2}1\,dV
  1. The inequality requires z≥0 and r²≤4. The projection is a disk of radius 2.

    0≤r≤2,0≤z≤4−r20\le r\le2,\quad0\le z\le4-r^2
  2. We can also slice at height z. Solve for the maximum radius; z is now the outer variable.

    0≤z≤4,0≤r≤4−z,0≤θ≤2π0\le z\le4,\quad0\le r\le\sqrt{4-z},\quad0\le\theta\le2\pi
  3. The volume integrand is 1; the Jacobian supplies r. Use the editor-supported order.

    V=∫04∫02π∫04−zr dr dθ dzV=\int_0^4\int_0^{2\pi}\int_0^{\sqrt{4-z}}r\,dr\,d\theta\,dz
  4. Integrate radially while treating z as constant.

    ∫04−zr dr=4−z2\int_0^{\sqrt{4-z}}r\,dr=\frac{4-z}{2}
  5. The angular integral gives 2π.

    V=π∫04(4−z) dzV=\pi\int_0^4(4-z)\,dz
  6. Evaluate height from 0 to 4 to obtain the volume.

    V=π[4z−z22]04=8πV=\pi\left[4z-\frac{z^2}{2}\right]_0^4=8\pi

Check the result and domain

Heights from 0 to 4 do not imply a height-4 cylinder: each slice has a different radius. Order dz dr dθ also works on this region, with different bounds.

∫02π∫02∫04−r2r dz dr dθ=8π\int_0^{2\pi}\int_0^2\int_0^{4-r^2}r\,dz\,dr\,d\theta=8\pi
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Now try it yourself

Solve on paper before opening the hint or answer. These are self-assessment activities; to check a typed answer, open Learn.

In these exercises θ runs from 0 to 2π: a full revolution is intended.

EXERCISE 1V(0≤r≤1, 0≤z≤3)V(0\le r\le1,\ 0\le z\le3)
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This is a full cylinder.

Check my result3π3\pi
EXERCISE 2∭0≤r≤1, 0≤z≤1z dV\iiint_{0\le r\le1,\ 0\le z\le1}z\,dV
Show a hint

The transformed integrand is z·r.

Check my resultπ2\frac\pi2
EXERCISE 3V(0≤z≤1−x2−y2)V(0\le z\le1-x^2-y^2)
Show a hint

Repeat the process with maximum height 1.

Check my resultπ2\frac\pi2
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