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Integration by parts

Material by the IntegralPaso project. Conditions and limits are stated in each guide; external teaching review is pending.

∫u dv=uv−∫v du\int u\,dv=uv-\int v\,du

Choose u so that its derivative simplifies the problem and dv so that its primitive is accessible. Compute du and v before substituting. LIATE is a guideline: logarithms, inverse trigonometric, algebraic, trigonometric and exponential functions. It does not guarantee the best choice in every case.

Choose a case

Common mistake

Losing the minus sign or choosing dv that is harder to integrate than the original problem.

Worked example

∫xex dx\int x e^{x}\, dx
  1. Identify the integrand, variables and order. For multiple integrals, start with the innermost integral.

    ∫xex dx\int x e^{x}\, dx
  2. Integrate with respect to x. Treat the other variables as constants at this stage.

    ∫xex dx\int x e^{x}\, dx
  3. Choose u and dv. Differentiate u and find a primitive v of dv.

    u=x,dv=ex dx,du=1 dx,v=exu=x,\quad dv=e^{x}\,dx,\quad du=1\,dx,\quad v=e^{x}
  4. Substitute into the integration by parts formula. The minus sign applies to the entire remaining integral.

    ∫xex dx=xex−∫ex dx\int x e^{x}\, dx = x e^{x} - \int e^{x}\, dx
  5. The exponential is its own derivative. Compensate any constant factor in the exponent.

    ∫ex dx=ex\int e^{x}\, dx = e^{x}
  6. Check this primitive by differentiating it: recover exactly the integrand of this stage.

    (x−1)ex+ex=xex\left(x - 1\right) e^{x} + e^{x} = x e^{x}
  7. Add the constant C: all primitives on an interval differ by a constant.

    (x−1)ex+C\left(x - 1\right) e^{x} + C
Result(x−1)ex+C\left(x - 1\right) e^{x} + C
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