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Identities

Trigonometric integrals

Material by the IntegralPaso project. Conditions and limits are stated in each guide; external teaching review is pending.

sin⁡2x=1−cos⁡(2x)2\sin^2x=\frac{1-\cos(2x)}{2}

In products of sine and cosine, an odd power lets you separate a factor and use substitution. For even powers, double-angle identities can reduce the degree. Roots such as √(a²−x²) suggest a trigonometric substitution, but an interval must be specified to control signs and roots.

Choose a case

Common mistake

Assuming √(cos²t) = cos t without checking the sign: in general it is |cos t|.

Worked example

∫sin⁡2(x) dx\int \sin^{2}{\left(x \right)}\, dx
  1. Identify the integrand, variables and order. For multiple integrals, start with the innermost integral.

    ∫sin⁡2(x) dx\int \sin^{2}{\left(x \right)}\, dx
  2. Integrate with respect to x. Treat the other variables as constants at this stage.

    ∫sin⁡2(x) dx\int \sin^{2}{\left(x \right)}\, dx
  3. Look for trigonometric identities that simplify the integrand, then apply integration rules to the resulting expression.

    sin⁡2(x)=sin⁡2(x)\sin^{2}{\left(x \right)} = \sin^{2}{\left(x \right)}
  4. Rewrite the expression in an equivalent form that is easier to integrate.

    sin⁡2(x)=12−cos⁡(2x)2\sin^{2}{\left(x \right)} = \frac{1}{2} - \frac{\cos{\left(2 x \right)}}{2}
  5. Split the sum. The integral of a sum is the sum of its integrals.

    ∫(12−cos⁡(2x)2) dx=∫12 dx+∫(−cos⁡(2x)2) dx\int \left(\frac{1}{2} - \frac{\cos{\left(2 x \right)}}{2}\right)\, dx = \int \frac{1}{2}\, dx + \int \left(- \frac{\cos{\left(2 x \right)}}{2}\right)\, dx
  6. Integrate a constant by multiplying it by the variable.

    ∫12 dx=x2\int \frac{1}{2}\, dx = \frac{x}{2}
  7. Move the constant factor outside: it does not depend on the integration variable.

    ∫(−cos⁡(2x)2) dx=−sin⁡(2x)4\int \left(- \frac{\cos{\left(2 x \right)}}{2}\right)\, dx = - \frac{\sin{\left(2 x \right)}}{4}
  8. Make a substitution and replace the differential too; both must change together.

    u=2x,du=2 dxu = 2 x,\quad du = 2\,dx
  9. Move the constant factor outside: it does not depend on the integration variable.

    ∫cos⁡(u)2 du=sin⁡(u)2\int \frac{\cos{\left(u \right)}}{2}\, du = \frac{\sin{\left(u \right)}}{2}
  10. Use the fact that the derivative of sin(x) is cos(x).

    ∫cos⁡(u) du=sin⁡(u)\int \cos{\left(u \right)}\, du = \sin{\left(u \right)}
  11. Combine the results of the substeps and simplify.

    ∫cos⁡(u)2 du=sin⁡(u)2\int \frac{\cos{\left(u \right)}}{2}\, du = \frac{\sin{\left(u \right)}}{2}
  12. After integrating the expression in u, return to the original variable.

    ∫cos⁡(2x) dx=sin⁡(2x)2\int \cos{\left(2 x \right)}\, dx = \frac{\sin{\left(2 x \right)}}{2}
  13. Combine the results of the substeps and simplify.

    ∫(−cos⁡(2x)2) dx=−sin⁡(2x)4\int \left(- \frac{\cos{\left(2 x \right)}}{2}\right)\, dx = - \frac{\sin{\left(2 x \right)}}{4}
  14. Combine the results of the substeps and simplify.

    ∫(12−cos⁡(2x)2) dx=x2−sin⁡(2x)4\int \left(\frac{1}{2} - \frac{\cos{\left(2 x \right)}}{2}\right)\, dx = \frac{x}{2} - \frac{\sin{\left(2 x \right)}}{4}
  15. Combine the results of the substeps and simplify.

    ∫sin⁡2(x) dx=x2−sin⁡(2x)4\int \sin^{2}{\left(x \right)}\, dx = \frac{x}{2} - \frac{\sin{\left(2 x \right)}}{4}
  16. Check this primitive by differentiating it: recover exactly the integrand of this stage.

    12−cos⁡(2x)2=sin⁡2(x)\frac{1}{2} - \frac{\cos{\left(2 x \right)}}{2} = \sin^{2}{\left(x \right)}
  17. Add the constant C: all primitives on an interval differ by a constant.

    x2−sin⁡(2x)4+C\frac{x}{2} - \frac{\sin{\left(2 x \right)}}{4} + C
Resultx2−sin⁡(2x)4+C\frac{x}{2} - \frac{\sin{\left(2 x \right)}}{4} + C
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